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A 66-kg water skier is being pulled by a nylon (Young's modulus 3. The unstretched length of the rope is 12 m and its cross-section area is 2.

A 66-kg water skier is being pulled by a nylon (Young's modulus 3.7 x 109 N/m2) tow rope that is attached to a boat. The unstretched length of the rope is 12 m and its cross-section area is 2.0 x 10-5 m2. As the skier moves, a resistive force (due to the water) of magnitude 160 N acts on her; this force is directed opposite to her motion. What is the change in length of the rope when the skier has an acceleration whose magnitude is 0.63 m/s2?

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T - 140 = m*a so, T = 140 + 64kg*0.90m/s^2 = 197.6N  Y(Young's... View the full answer

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