Realize that for the particle to go straight, the electric force must equal the magnetic force: q E = q vB
A device ("source") emits a bunch of charged ions (particles) with a range of ve- locities (see figure). Some of these ions pass through the left slit and enter "Region I" in which there is a vertical uniform electric field (in the −ˆ direction, due to the potential dif- ference 2500 V across the distance 0.7 cm) and a 0.3 T uniform magnetic field (aligned with the ±kˆ-direction) as shown by the shaded area. ˆı is in the direction +x (to the right), ˆ is in the direction +y (up the page), and kˆ is in the direction +z (out of the page).
The ions that make it into "Region II" are observed to be deflected downward and then follow a circular path with a radius of r = 0.52 m.
If the charge on each ion is 1.9 × 10−18 C , what is the mass of the ions? (There is mag- netic field in both Region I and Region II.)
Answer in units of kg.
Given That the particle to go straight , the electric force must equal the magnetic force so qE = qvB The... View the full answer
- This is the same answer i keep getting also, however it is incorrect according to my homework
- Apr 03, 2018 at 2:12pm