A 5.00 kg pumpkin oscillates from a vertically hanging light spring once every 0.60 s.

(a) Calculate the equation giving the pumpkin's position *y* (+ upward) as a function of time *t*, assuming it started by being compressed 9.0 cm from the equilibrium position (where *y* = 0), and released. (Use the following as necessary: *t*. Assume *t* is in s and *y* is in m.)

*y*=_________

(b) How long will it take to get to the equilibrium position for the first time?

_______s

(c) What will be the pumpkin's maximum speed?

______m/s

(d) What will be its maximum acceleration, and where will that first be attained?

______m/s^{2}

^{Please explain, thank you }

#### Top Answer

y = 0.09 *cos(10.472t) b. It will take 0.15s to get the equilibrium position for the... View the full answer