A 5.00 kg pumpkin oscillates from a vertically hanging light spring once every 0.60 s.
(a) Calculate the equation giving the pumpkin's position y (+ upward) as a function of time t, assuming it started by being compressed 9.0 cm from the equilibrium position (where y = 0), and released. (Use the following as necessary: t. Assume t is in s and y is in m.)
(b) How long will it take to get to the equilibrium position for the first time?
(c) What will be the pumpkin's maximum speed?
(d) What will be its maximum acceleration, and where will that first be attained?
Please explain, thank you
y = 0.09 *cos(10.472t) b. It will take 0.15s to get the equilibrium position for the... View the full answer