I had a question concerning the FBFD in my Lab report
i set it like this
im just unsure whether the pink arrow would be treated as a normal force or the tension force in the X axis?
i believe i got part b correct, my answers being Ax = (Tcos)/m & Ay = (Tsin)/m - g, A being acceleration x/y being subscripts.
would the location used to determine the length start from where the bob is attached to the string?
& i don't really understand part c, all i can write down is v = ( 2pi R )/p & A = (4pi^2 R )/p^2 where R = radius & p = period
a) Your free body diagram is right though your values are wrong. We have the vertical angle as theta. So T x = T sin(theta)... View the full answer