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FBFD in my Lab report i set it like this im just unsure whether the pink arrow would be treated as a normal force or the tension force in the X axis?...

I had a question concerning the FBFD in my Lab report

phys lab.jpg

i set it like this

723335076fee3d8c1e62d5dae48c7e9e.png

im just unsure whether the pink arrow would be treated as a normal force or the tension force in the X axis?

i believe i got part b correct, my answers being Ax = (Tcos)/m & Ay = (Tsin)/m - g, A being acceleration x/y being subscripts.

would the location used to determine the length start from where the bob is attached to the string?

& i don't really understand part c, all i can write down is v = ( 2pi R )/p & A = (4pi^2 R )/p^2 where R = radius & p = period

723335076fee3d8c1e62d5dae48c7e9e.png

phys lab.jpg

Top Answer

a) Your free body diagram is right though your values are wrong. We have the vertical angle as theta. So T x = T sin(theta)... View the full answer

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