A uniform thin rod of mass M = 4.51 kg pivots about an axis through its center and perpendicular to its length. Two small bodies, each of mass m = 0.549 kg, are attached to the ends of the rod. What must the length L of the rod be so that the moment of inertia of the three-body system with respect to the described axis is I = 0.957 kg·m2?
The length of the rod must be... View the full answer
- Note: Precise answer is L = 1.213 m.
- May 08, 2018 at 10:43pm