In a hydrogen atom, the electron jumps from n=1 level to the n=4 level. What is the wavelength of the emitted or absorbed photon?

#### Top Answer

the wavelength of the photon is given by lambda=hc/E where h... View the full answer

- also you can get by finding the energy difference that is =n=1=-13.6ev ,n=4=0.85ev ,the difference is 12.75ev convert to joules wihich is multiply by 1.6*10^-19=2.04*10^-18j, using formula of finding lambda= (6.63*10^-34j*3.0*10^8)/(2.04*10^-18j)=9.75*10^-8m
- gohcollins
- May 15, 2018 at 11:30am

#### Sign up to view the full answer

#### Other Answers

Wavelength of the emitted or... View the full answer

- "Calculation Mistake"Energy in above Equation = 12.75 ev = 2.04*10^-18 J, Because it jumping from N=1 to N=4, Hence wavelength = h*c / 2.04*10^-18 J =9.744 * 10^-8 meter.
- radhey9
- May 15, 2018 at 1:55pm

The wavelength of the... View the full answer