An electron in the third stationary state around a hydrogen atom has energy of -1.512 eV. What will the electron's energy be if the hydrogen atom absorbs a photon with a wavelength of 109 nm?
Given, wavelength λ = 1 0 9 n m = 1 . 0 9 × 1 0 − 7 m Energy of the photon corresponding to the above... View the full answer
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the electron energy formula is given by=E=hc/(lambda) therefore we have been given... View the full answer