Tarzan 95 kg is perched on a cliff 14.0 m above Jane.
Part A: What is the value of Tarzan's speed (vT) just as he gets down to Jane's level?
Part B: If Tarzan is actually moving at 10.5 m/s, what fraction (%-loss) of kinetic energy did he lose due to air resistance?
Part C: If Tarzan's mass were 40% greater, how would that affect the answer for Part A? His speed would be...
exactly the same
Since Tarzan is perched the initial velocity u = 0 Part A: Applying the equation. 2gs = v 2 —u 2 . Since u = 0 Then 2gs= v... View the full answer