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I just need the solution for part B, please.

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A shopper weighs 2.50 kg of apples on a supermarket scale whose spring obeys Hooke's law and notes that the spring stretches a distance of
2.50 cm. (a) What will the spring's extension be if 5.50 kg of oranges are weighed instead?
5.5 v cm (b) What is the total amount of work that the shopper must do to stretch this spring a total distance of 6.00 cm beyond its relaxed position?
1.48225 x Your response differs from the correct answer by more than 10%. Double check your calculations. J

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