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# for b. I got a negative answer but it's about height so it

should be positive but I don't know where I went wrong in my calculations. I used the equation (max height = V initial^2(sin of initial angle)^2 / 2(gravity)). I did v initial as 25 m/s and sin of 32 and gravity as -9.81 (because it's going down but when the did it on my calculator I got -8.94m.

Ii ‘ humHIW-Ilsmhrdsbsa/i x | V SCN2797-145805:Projec x e assignmemﬁmwf K 15 Unit A Assessment Marks This assignment is worth 15 marks. The value of each question is noted in the left margin in
Total parentheses. Note: The answer areas will expand to ﬁt the length of your response. 1. You are standing on the top of a tall cliff and shoot an arrow from a height of 30.0 m at
25.0 mls and an initial angle of 32.0” above the horizontal. Show all your work in calculating the answers to the following questions. You may check your work using any
of the simulations you have previously used in Unit A. a. What are the horizontal and vertical components of the arrow's initial speed? b. How high above the base of the cliff will the arrow rise? Assume a level
landscape. c. How far off course will the arrow be after 3.35 s if there is a 12.0 mls
crosswind?

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