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This is an elementary problem in... View the full answer

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Y=15
P=5
V = 56cc
- 10 0
V = 15 3) V = 56
Y. = 5
V 2
15
=) V3 = 56
a
GE
TI = JOC = 283K
2 = 3. 73 ce
(Va = 11-2 cc)
1 - 2 adiabatic process
TIVITY = TV!
PV = P, V 2
=) 283 V 1 4-1 = T V 1-4 -1
=)...

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