ictional heat and some energy is converted to electrical energy an hus the center of mass of the pendulum does not rise to the same right, h, See...
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src="/qa/attachment/10819169/" alt="media_2e5_2e5798c3-9687-49d7-bdb4-1e4aa29b1e69_image.jpg" />How to prove equation 19(total energy lost=mgl(1- cos (theta))?

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ictional heat and some energy is converted to electrical energy an
hus the center of mass of the pendulum does not rise to the same
right, h, See Figure Il
The total energy lost by the pendulum is equal to its chang
Total Energy Lost = AU=mg (h, -h)
Total Energy Lost = AU = mg/ (1-coso)
there / is the distance from the pivot point to the center of mass
asition of the coil wand
Centre of mass
C
Figure II: Col Height Decreases
The thermal energy dissipated in the resistor ( R ) is given
Figure
E =[P di = SP Ar

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Version 20
NEO3 - Faraday's Law of Induction
Energy and Power
If the center of mass of the pendulum starts from rest at an initial height A , it's potential energy is
U - mgh,
(17)
As the pendulum swings and passes through the magnet, some energy is lost to mechanical
frictional heat and some energy is converted to electrical energy and then to thermal energy in the resistor.
Thus the center of mass of the pendulum does not rise to the same height but rather to a lower final
height, h, See Figure 11.
The total energy lost by the pendulum is equal to its change in potential energy;
Total Energy Lost = AU = ng (h, -4)
(18)
Total Energy Lost = AU = mg/ (1-cose)
(19)
where / is the distance from the pivot point to the center of mass of the coil wand, and & is the angular
position of the coil wand

Top Answer

It must be; Delta U = mgl... View the full answer

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Initial and final gravitational... View the full answer

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4 ( Pivot)
I coSQ
(reference
$4 ( centre of
level) hem
mass )
- - - (.- - -.
. ( =0)
- .
( initial - position )
Let potential energy at
Final-position
reference level be zero.
so U, = mx g x hom...

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