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How do I solve a problem like this ? If you strap a 10- kg weight to your heel and then straighten out your leg

as shown in the diagram, calculate the torque around your knee joint due to the weight at each of the four angles indicated.

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The torque can be on different angles When angle = 0, torque =... View the full answer

New Doc 2019-11-05 01.52.34_1.jpg

Vqo
40 CM
30
M = 10 kg
Torque ( I ) = rXF = RX F X Sin A
force due to weight = mass x 9 = 10 xq x 9 .8 = 98N
1 = distance between force applied and hope joint
40 cm . = 0.4m . A = angle between...

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