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Hello, could you please help me out with this question?


An object suspended from a spring with

a spring constant of 2.56N/m vibrates with a frequency of 0.148 HZ. Refer to a 0.250 kg pendulum.

a. What length of the pendulum is needed to oscillate at the same frequency as the object?

b. What is the restoring force on the pendulum at an angle of 6.24 degrees from the equilibrium position?


Thank you in advance.

Top Answer

Hi Dear , To calculate " part (a)" we will find out the value of time period( T ) from the value of given frequency( f ) by... View the full answer

New Doc 2020-01-03 08.49.12.jpg

( a ) Time -period ( T ) of the pendulum-
T = 2A
I s length of the pendulum .
Frequency and time -period are related as
f = = = T = = 0148
1 8 = 6.76 seconds
From ( 1 )
T = 27
= 6.76
=
6.76
= 1075...

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