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I have found that

Ω(N, α_a, α_b) = e^(2N)(α_a*α_b)^N. However, when I take the ln of this, I get 2N + Nln(α_a) + Nln(α_b). How can I use the Stirling Approximation on this to get this expression?

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= -Nalna + (1 - a) In(1 - Q)] + 0(In N)
Using this together with your answer from part (b), show that
In Q(N, QA, QB) =
-NaAmaA + (1 - QA) In(1 - QA) +aBlas + (1 - QB) In(1 - QB)] + O(In N)

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See the explanation. I guess my omega is... View the full answer


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