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A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt^2+qt

with p = 0.40 m/s^2 and q = -1.40 m/s. Determine the mouse's average velocity between t = 1.0 s and t = 4.0 s. 

Top Answer

We have x ( t ) = p t 2 + q t velocity is given by, v ( t ) = d t d x ( t ) = 2 p t + q Average velocity... View the full answer

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