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An electron remains suspended between the surface of the Earth (assumed neutral) and a fixed positive point

charge, at a distance of 11.76 m from the point charge. Determine the charge required for this to happen. The acceleration due to gravity is 9.8 m/s 2 and the Coulomb constant is 8.98755 × 109 N · m2 /C 2 . Answer in units of C. 

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Force exerted on the charge is F = k e qq e /r 2 = m e g Given: Mass... View the full answer

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