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# Hi, I really need help with my study questions.

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Q3 a) 1.664 x 10 6 J b) 2.77 x 10 6 J... View the full answer

work done = mxgx ( 2 )
= 7 8 6 * 4 x 3 5 2 x 6 7 x 9 . 8 x 2
as mass of 2
&quot; &quot;past = 7 8 6 X 4 X 3X 2 X6
work done = 7.394 x 105 J
ATONTTE h = ( 2+2 ) = 4m
so work done = 7 8 6 x 4 x 3 x 2...

work done = mgh
top of tank
I
6m
COM
so considering com
motion .
h= 3m
and work done = m x 9. 8x 3
NO
m = e x V = 7 8 6 x 4 x 3X6
work done = 16 63 804. 8J
work done = 1. 664 x16 6 J
When 2 m above...

each bit of chain that is lifted to top of
building can secured, there. say by putting
link over some kind of beg
W =
( F. dz
F =
( 7 2 - 2 ) X 27 / X J .8
7 2
mass of the past that is hanging.
Do...

Questions are solved using the formula of potential energy .... View the full answer

Height of centre of mass
of hanging length from top is
h2 = 64 = 32 m
h2
Final potential energy is-
U , = _ m , xg x hz
mass of hanging part
72m has mass 23 up
6am has mass 23 x648
My = 20. 94 ng...

( 4) mass of 2rd
of liquid
is
My =
xxd = 12x6
- x 786 = ( 2 4 x 7 86 ) 2 18869
height of 2rd
rd of liquid
from bottom = 2 x6 = am
C.MY
2 m
IT
position of centre of
mass of 2 01
of liquid
from top...

3. (3 points) A rectangular tank that is 4 meters long, 3
meters wide and 6 meters deep is ﬁlled with a rubbing alcohol
that has density 786 kilograms per cubic meter. In each part
below, assume...

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