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A car drives along a dual carriageway at 96 km h1. The driver sees a speed limit sign approaching and applies the brakes to decelerate to a speed of...

A car drives along a dual carriageway at 96 km h−1. The driver sees a speed limit sign approaching and applies the brakes to decelerate to a speed of 48km h−1. Given that the deceleration is 2.68 m s−2 find the distance over which
the brakes are applied.
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Dear Student, Please check the attached solutions file of... View the full answer

phy.pdf

Initial speed = 96 km/hr
Final speed = 48 km/hr
1 km/hr = 5/18 m/s
thus
initial speed = 96x5/18 = 80/3 m/s
final speed = 48x5/18 = 40/3 m/s
acceleration = -2.68 m/s2
Now using Newton’s equation...

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