(a) Calculate the rotational inertia of the pendulum about the pivot.
(b) What is the distance between the pivot and the center of mass of the pendulum?
(c) Calculate the period of oscillation.
Plz help. Thanks.Let me analyze your thinking. This is straightforward.I thought I can find (a) by adding the rotational inertia of the rod and the disk.
I = 1/3 ML^2 + 1/2 mr^2
I wonder in this case, what's the rotational inertia of the disk? Is that
I=1/2 mr^2 + m(L+r)^2?
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