Suppose the skin temperature of a naked person is 34°C when the person is standing inside a room whose temperature is 25°C. The skin area of the individual is 2.0 m2.(a) the emissivity is 0.80, find the net loss of radiant power from the body. (b) Determine the number of food Calories of energy (1 food Calorie = 4186 J) that is lost in one hour due to the net loss rate obtained in part (a). Metabolic conversion of food into energy replaces this loss.

### Recently Asked Questions

- How can i make the set of a,b,c repeat 3 times( as in triplicate of a,b,c) %Pythagorean Triplet %Find the two Pythagorean Triplets for which a + b + c = n % a,

- how ineffective communication and resource constraints can impact on time-management within projects?

- how do I find four ordered pair solutions by completing the table and then use the ordered pairs in a graph for y = 1/3x -1 with x y -3 0 0 1 2.I need help