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At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight. The spring set the full bunch of bananas into vertical...

This question was answered on Apr 24, 2010. View the Answer
At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight.  The spring set the full bunch of bananas into vertical oscillatory motion.  The motion is harmonic with an amplitude of 0.15 m.  The spring of the scale has a force constant k = 332 n/m.  It is observed that the maximum speed of the banans is 1.56m/s.  
What is the mass of the banana bunch in units of kg?

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Dear Student please find... View the full answer

bananna problem solve.doc

X(t) = Asin(wt) where w= omega
differentiating wrt time again
v(t) = Aw cos(wt)
for maximum velocity
Vmax = Aw whee A is max amplitude of SHM
or 1.56m/s = 0.15m x (√(k/m) where k = 332n/m
so m =...

This question was asked on Apr 24, 2010 and answered on Apr 24, 2010.

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