View the step-by-step solution to:

At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight. The spring set the full bunch of bananas into vertical...

At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight.  The spring set the full bunch of bananas into vertical oscillatory motion.  The motion is harmonic with an amplitude of 0.15 m.  The spring of the scale has a force constant k = 332 n/m.  It is observed that the maximum speed of the banans is 1.56m/s.  
What is the mass of the banana bunch in units of kg?

Top Answer

Dear Student please find... View the full answer

bananna problem solve.doc

X(t) = Asin(wt) where w= omega
differentiating wrt time again
v(t) = Aw cos(wt)
for maximum velocity
Vmax = Aw whee A is max amplitude of SHM
or 1.56m/s = 0.15m x (√(k/m) where k = 332n/m
so m =...

Sign up to view the full answer

Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

-

Educational Resources
  • -

    Study Documents

    Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

    Browse Documents
  • -

    Question & Answers

    Get one-on-one homework help from our expert tutors—available online 24/7. Ask your own questions or browse existing Q&A threads. Satisfaction guaranteed!

    Ask a Question
Ask a homework question - tutors are online