615 nm light is incident on a single slit that is .25 mm in width. The observing screen is 3 m away. find the position of the first dark fringe and the width of the central bright fringe

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- For confidence coefficient .99 , 1 - α = .99 ⇒ α = 1 - .99 = .01 . α/2 = .01/2 = .005 . Z α/2 = z .005 = 2.575 . The 99 % confidence interval for p is :

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