A car travels forward with constant velocity. It goes over a small stone, which gets stuck in the groove of a tire. The initial acceleration of the stone, as it leaves the surface of the road is,
e)greater than zero but less than 45 degrees below the horizontal
I think the answer would be d)zero since the car's tire is going at constant velocity. Would my thinking be correct?
The correct answer is "vertically up". The car's tire is going at constant speed, but the velocity is constantly changing direction. The instantaneous velocity of the part of the tire that is in contact with the road is zero, so the stone is not subjected to a tangential acceleration.
From the moment it is caught in the tire it is rotating with the tire. An object that is rotating around some point with constant speed is accelerating toward that point with the centripetal acceleration of v^2/r.
Recently Asked Questions
- Please refer to the attachment to answer this question. This question was created from ACC 440 Final Exam Review.pdf. Additional comments: "can you explain
- When unemployment begins to climb to unacceptable levels in the economy, the government should: use contractionary fiscal policy to shift aggregate demand to
- (LO 8) Factor Co. can produce a unit of product for the following costs: Direct material $ 7.60 Direct labor 23.60 Overhead 38.00 Total costs