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# A 30g bullet with a horizontal velocity of 500m/s comes to a stop 12 cm within a solid wall. a) what is the change in its mechanical energy?

A 30g bullet with a horizontal velocity of 500m/s comes to a stop 12 cm within a solid wall.
a) what is the change in its mechanical energy?
b) What is the magnitude of the average force from the wall stopping it?
a) what would I use of the equation? Can you please explain what i would do? I am confused
b)Would I use F= ma?a) The original mechanical energy is the kinetic energy. It goes from
(1/2) M Vo^2 to zero. Vo is the initial velocity, 500 m/s
b) (average Force) x (stopping distance) = mechanical energy loss
Solve for the average force

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