A 30g bullet with a horizontal velocity of 500m/s comes to a stop 12 cm within a solid wall.

a) what is the change in its mechanical energy?

b) What is the magnitude of the average force from the wall stopping it?

a) what would I use of the equation? Can you please explain what i would do? I am confused

b)Would I use F= ma?a) The original mechanical energy is the kinetic energy. It goes from

(1/2) M Vo^2 to zero. Vo is the initial velocity, 500 m/s

b) (average Force) x (stopping distance) = mechanical energy loss

Solve for the average force

a) what is the change in its mechanical energy?

b) What is the magnitude of the average force from the wall stopping it?

a) what would I use of the equation? Can you please explain what i would do? I am confused

b)Would I use F= ma?a) The original mechanical energy is the kinetic energy. It goes from

(1/2) M Vo^2 to zero. Vo is the initial velocity, 500 m/s

b) (average Force) x (stopping distance) = mechanical energy loss

Solve for the average force

## This question was asked on May 11, 2010.

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