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A beam resting on two pivots has a length of L = 6.00 m and mass M = 81. The pivot under the left end exerts a normal force n1 on the beam, and the...

A beam resting on two pivots has a length of L = 6.00 m and mass M = 81.4 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance l = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 44.1
kg steps onto the left end of the beam and begins walking to the right
as in the figure below. The goal is to find the woman's position when
the beam begins to tip.

(a) Sketch a free-body diagram, labeling the gravitational and normal
forces acting on the beam and placing the woman x
meters to the right of the first pivot, which is the origin. (Do this
on paper. Your instructor may ask you to turn in this work.)
(b) Where is the woman when the normal force n1
is the greatest?

This question was asked on May 24, 2010.

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