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A woman who weighs 5.00X10^2 Newton’s is...
This question was answered on May 30, 2010. View the Answer
A woman who weighs 5.00X10^2 Newton’s is leaning against a smooth vertical wall. The angle of her body with respect to the ground is 60 degrees. Her center of gravity is located 1.10 meters from the ground and 0.400 meters below where her shoulder touches the wall. Find (a) the Force FN (directed perpendicular to the wall) exerted on her shoulders by the wall and the (b) horizontal and (c) vertical components of the force exerted on her shoes by the ground.Topic: Rotational Dynamics

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