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# Four identical masses of mass 500 each are placed at the corners of a square whose side lengths are 13.

Four identical masses of mass 500 each are placed at the corners of a square whose side lengths are 13.0cm. What is the magnitude of the net gravitational force on one of the masses, due to the other three?

Dear Student, Please check the attached solutions file of... View the full answer

→ Gm1 m4/r2
m1 m4
Gm1m3 / ()2 Gm1m2
m2 m3 The force of attraction between 2 masses is given by;
F = Gm1m2 / r2
r = distance between masses
Let each side of the square = r
Force on m1 due to m2
=...

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