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# Four identical masses of mass 500 each are placed at the corners of a square whose side lengths are 13.

Four identical masses of mass 500 each are placed at the corners of a square whose side lengths are 13.0cm. What is the magnitude of the net gravitational force on one of the masses, due to the other three?

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Dear Student, Please check the attached solutions file of... View the full answer

→ Gm1 m4/r2
m1 m4
Gm1m3 / ()2 Gm1m2
m2 m3 The force of attraction between 2 masses is given by;
F = Gm1m2 / r2
r = distance between masses
Let each side of the square = r
Force on m1 due to m2
=...

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