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A 25 g bullet strikes and becomes embedded in a 1.30 kg block of wood placed on a horizontal surface just in front of the gun.

A 25 g bullet strikes and becomes embedded in a 1.30 kg block of wood placed on a horizontal surface just in front of the gun.If the coefficient of kinetic friction between the block and the surface is 0.24, and the impact drives the block a distance of 9.1 m before it comes to rest, what was the muzzle speed of the bullet?

Initial velocity of bullet is u
After collision its velocity is v
m= mass of bullet
M= mass of box
So, mu =(M+m)v [conservation of momentum]
Or, v = F = frictional force =
From conservation of...

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