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# PSS 25.1 Electromagnetic induction Learning Goal: To practice Problem-Solving Strategy 25.1 Electromagnetic induction. A loop of wire of radius = 40....

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PSS 25.1 Electromagnetic induction Learning Goal: To practice Problem-Solving Strategy 25.1 Electromagnetic induction. A loop of wire of radius = 40. has an electrical resistance = 0.039 . The loop is initially inside a uniform magnetic field of magnitude = 1.8 parallel to the loop's axis. The magnetic field is then reduced slowly at a constant rate, which induces a current = 0.20 in the loop. How long does it take for the magnitude of the uniform magnetic field to drop from 1.8 to zero? PROBLEM-SOLVING STRATEGY Electromagnetic induction PREPARE Make simplifying assumptions about wires and magnetic fields. Draw a picture or a circuit diagram. Use Lenz's law to determine the direction of the induced current. SOLVE The mathematical representation is based on Faraday's law . For an N-turn coil, multiply by . The size of the induced current is . ASSESS Check that your result has the correct units, is reasonable, and answers the question. Prepare Assume that at any time the magnetic field is uniform inside the coil and that, when the field is decreased, it changes magnitude but not direction. Note that the resistance of the coil and the induced current are assumed to be constant and of known magnitudes. Part A The sketch shows the coil lying in the plane of the screen and the external magnetic field pointing into the screen. As the external magnetic field decreases, an induced current flows in the coil. What is the direction of the induced magnetic field caused by this current? Hint A.1 Lenz's law Hint not displayed Hint A.2 Identify how the magnetic flux changes Hint not displayed
ANSWER: The field points radially outward from th the coil. The field points radially inward toward t the coil. The field points vertically upward in the screen. The field points vertically downward in the screen. The field points into the screen. The field points out of the screen. Solve
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Solve
Flux Φ= B A = 1.8( pi*(0.04)^2)
Emf = -d Φ / dt
Current I = emf / R
I = - [d Φ /dt ]*1/R
0.2 = [1.8( pi*(0.04)^2)/ t ] *1/0.039
T = [1.8( pi*(0.04)^2)/ 0.2 ] *1/0.039= 1.1599 sec

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