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Name____________________________ Physics 1012 Laboratory 3, Forces Objective: Find the kinetic friction between two objects. For this problem, we...

Enter your measurements for m1,m2,y, and t below. Then use the equations you found above to calculate the acceleration and friction force.

m1 = 0.03 kg
m2 = 0.08 kg
y = 0.6 m
t = 1.8 s

acceleration = ?
friction force = ?

Use g=9.8m/s^2

Name____________________________ Physics 1012 Laboratory 3, Forces Objective: Find the kinetic friction between two objects. For this problem, we need to look at the two objects separately. Mass 1: Start with Newton’s 2 nd Law: F net = m a W-T= m 1 a m 1 g – T = m 1 a T = ____________ Mass 2: Since mass 2 is on a flat surface and is not accelerating vertically, N = W 2 = m 2 g so f = μ k m 2 g F net = m a T – f = m 2 a Insert your equation for T and solve for f f = ______________ What is the acceleration? (Definitely not 9.8m/s 2 ) Our favorite kinematics equation can help us with that: y = ½ a t 2 a = _______________ Here, y is the distance the 2 nd mass falls which should be the same as the distance the block moves horizontally. m 1 m 2 t a f
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Procedure: For your mass 2, you will use the wooden block or the blue cart turned upside down. You will need to make your own mass 1. One possibility is to put 10 pennies in a plastic bag and use a paperclip as a hook. This should be about 30 grams (each penny is 2.5 grams + 5 gram bag). Use your spring scale to find the both masses. You want just enough mass so that the block moves smoothly. The slower it goes, the easier it will be to time. Place mass 2 on a table or desk and connect it to mass 1 with string. The string connecting the two should be about the same length as the height of the table. Pull mass 2 back as far as you can and let it go. Use your stopwatch to time how long it takes before the hanging mass hits the ground m1 m2 T f W T
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Physics-8364774.doc

8364774
T=m1a+m2a
Friction f=m1a+m2a-m2a
=m1a
Acceleration a=√2y/t
m1 = 0.03 kg
m2 = 0.08 kg
y = 0.6 m
t = 1.8 s
acceleration = ?
friction force = ?
Use g=9.8m/s^2
acceleration=0.816 m/s2...

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