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According to special relativity, the energy and momentum of a particle are E = mc2 /{1v2/c2} and [(p)\vec] = m[(v)\vec] /{1v2/c2} Show that E2 p2c2...

According to special relativity, the energy and momentum of a particle are
E = mc2 /√{1−v2/c2} and [(p)vec] = m[(v)vec] /√{1−v2/c2}
Show that E2 − p2c2 is invariant. If v = 9.00E+7 m/s, and m = 265.0 MeV/c2, what is √{E2−p2c2}?

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