60.0 mi/h for a distance d and then another distance d in
the same direction at another constant speed. The average
velocity for the entire trip is 30.0 mi/h. (a) What is the constant
speed with which the car moved during the second
distance d? (b) What If? Suppose the second distance d
were traveled in the opposite direction; you forgot something
and had to return home at the same constant speed
as found in part (a). What is the average velocity for this
trip? (c) What is the average speed for this new trip
This question was asked on Jan 28, 2013.
Recently Asked Questions
- Answer the following questions in 1,050 words using the Lachlin Corporation Balance Sheet located on p. 575 of Financial Accounting : How many shares of
- I've gotten partway through this problem, but I'm having trouble simplifying the algebra to find pareto efficient allocation expression.
- Question1, Determine the values of a for which the system has no solution, exactly 1 solution or infinitely many solutions: x + 2y + z = 2 2x − 2y + 3z = 1 x