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# An inclined plane of angle θ = 20.0° has a spring of force constant k = 520 N/m fastened securely at the bottom

so that the spring is parallel to the surface as shown in the figure below. A block of mass m = 2.59 kg is placed on the plane at a distance d = 0.324 m from the spring. From this position, the block is projected downward toward the spring with speed v = 0.750 m/s. By what distance is the spring compressed when the block momentarily comes to rest?

Sol: Given that
Let is the distance. By using energy conservation,
Now out all these values in above equation, we get
Taking a positive value,
So at the spring is compressed when the block...

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