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# Three point charges lie along the x -axis. A positive charge q1= 15x10^-6 C is at x=2m, and a positive charge of q2=6x10^-6 C is at the origin.

Three point charges lie along the x -axis. A positive charge q1= 15x10^-6 C is at x=2m, and a positive charge of q2=6x10^-6 C is at the origin. Where must a negative charge q3 be placed on the x -axis between the two positive charges such that the resulting electric force on q3 is zero.

Sign up to view the entire interaction Here we will put q1=15*10^-6 and q2= 6*10^-6
Then we solve for P Then we will get P= 1.22m
So q3 is placed x=1.22 to get zero force

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