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# A 7,600-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the collision and move with...

A 7,600-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the collision and move with speed 5 m/s. What was the speed of the truck before the collision?

from momentum conservation;... View the full answer

• to 2 decimal places= v = 5.66
• jemackd
• Apr 06, 2016 at 12:21pm
• this is arrived at by making v the subject formula. m1v1=m2v2, so v1=(m2v2)/m1
• jemackd
• Apr 06, 2016 at 12:21pm

m1v1 +m2v2 = (m1+m2)V 7600*V... View the full answer

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