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# What is the angle between vectors A and B if A =7^3^ and B =4^+2^?

What is the angle θ between vectors A⃗ and B⃗ if A⃗ =7ı^−3ȷ^ and B⃗ =−4ı^+2ȷ^?

|A| = sqrt(7^2 + (-3)^2) = sqrt(49 + 9) = sqrt(58) |B| = sqrt(4^2 + (2)^2) =... View the full answer

recall that    A.B = a b cosθ then    θ = cos -1 ( A.B / ( a b ) ) where  ... View the full answer

1 comment
• Aesio1980
• Apr 10, 2016 at 1:33am

Cos(theta) = A*B / |A|*|B| A*B = 7*-4 - 3*2 = -28 - 6 = 34 |A|=sqrt(7 2 + (-3) 2 )=sqrt(49... View the full answer

1 comment
• A*B = -34
• SIJO_VM
• Apr 10, 2016 at 1:37am

using  the equation cos(theta) = (A*B)/(|A||B|), where A*B is the dot product of the 2 and... View the full answer

1 comment
• 100% correct
• jackobkennedy
• Apr 10, 2016 at 1:42am

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