**What is the angle θ between vectors A⃗ and B⃗ if A⃗ =7ı^−3ȷ^ and B⃗ =−4ı^+2ȷ^?**

#### Top Answer

|A| = sqrt(7^2 + (-3)^2) = sqrt(49 + 9) = sqrt(58) |B| = sqrt(4^2 + (2)^2) =... View the full answer

#### Sign up to view the full answer

#### Other Answers

recall that A.B = a b cosθ then θ = cos -1 ( A.B / ( a b ) ) where ... View the full answer

- please, check and tell me if the answer is ok
- Aesio1980
- Apr 10, 2016 at 1:33am

Cos(theta) = A*B / |A|*|B| A*B = 7*-4 - 3*2 = -28 - 6 = 34 |A|=sqrt(7 2 + (-3) 2 )=sqrt(49... View the full answer

- A*B = -34
- SIJO_VM
- Apr 10, 2016 at 1:37am

using the equation cos(theta) = (A*B)/(|A||B|), where A*B is the dot product of the 2 and... View the full answer

- 100% correct
- jackobkennedy
- Apr 10, 2016 at 1:42am