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For a 10.0 C charge into a region with electric field E = 6.00x10 3 N/C i find change in electric potential energy when: a) the charge is moved 8.

For a 10.0 μC charge into a region with electric field E = 6.00x103 N/C i find change in electric potential energy when: a) the charge is moved 8.00 cm in the positive x-direction, b) the charge is moved 8.00 cm in the negative x-direction, c) the charge is moved 8.00 cm in the positive y-direction.


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Recall that W = - ΔU then, the change in electric potential energy is ΔU = - W ΔU = - F E . Δ r ΔU = - q E . Δ r hence... View the full answer

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