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# Suppose a small medical flashlight operating at a voltage of 9 V has a resistance of 8 ohms. How many electrons pass through the bulb filament per

Suppose a small medical flashlight operating at a voltage of 9 V has a resistance of 8 ohms. How many electrons pass through the bulb filament per second? Answer is 7.0 x 10^8 but don't remember how I got the answer

The way to approach this... View the full answer

number of electron... View the full answer

Voltage V=9 V
Resistance R=8 ohm
So current I=V/R
=9/8
=1.125 A
Current =charge/time
Charge= current*time
charge=1.125 x 1=1.125C
1 electron has charge 1.6*10-19 C
so 1.6 x 10-19 C c =1 electron...

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