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Suppose a small medical flashlight operating at a voltage of 9 V has a resistance of 8 ohms. How many electrons pass through the bulb filament per

This question was answered on Jul 19, 2016. View the Answer

Suppose a small medical flashlight operating at a voltage of 9 V has a resistance of 8 ohms. How many electrons pass through the bulb filament per second? Answer is 7.0 x 10^8 but don't remember how I got the answer

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The way to approach this... View the full answer

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number of electron... View the full answer

please view attached doc to... View the full answer

THE SOLUTION TO QUESTION.docx

Voltage V=9 V
Resistance R=8 ohm
So current I=V/R
=9/8
=1.125 A
Current =charge/time
Charge= current*time
charge=1.125 x 1=1.125C
1 electron has charge 1.6*10-19 C
so 1.6 x 10-19 C c =1 electron...

This question was asked on Jul 19, 2016 and answered on Jul 19, 2016.

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