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Consider an optical fiber of 0.5 cm diameter and a length of 10m.

Consider an optical fiber of 0.5 cm diameter and a length of 10m. If light is incident at the minimum angle to achieve total internal reflection, calculate the distance between successive reflections off the top core/cladding boundary. Assume the core fiber has an index of refraction of 1.38 and the cladding has an index of refraction of 1.21. Show all steps and drawings..etc. I think the answer was 1.8cm  but not sure how to get it

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n1= 1.38 n2= 1.21 critical angle Ө c = sin -1 n2/n1 =sin -1 (1.21/1.38)=61.26˚ The angle... View the full answer

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