Please answer using kinematics in 1 dimension and show completevanswers.
a cement block accidentally falls from rest from the ledge of the 35.0 m high building. When block is 14.0 m above the ground, a man 2.00 m tall looks up and noticed that the block is directly above him. How much time at most, does the man have to get out of the way?
part 1: block falls 35-14= 21m from equation of final velocity^2= initial velocity^2+ 2ad vf^2=vi^2+2ad a= gravitational... View the full answer
- i mean :time =-change in velocity/ acceleration= -(25.4323 -20.2879)/-9.8 = 0.52493 seconds
- Jul 20, 2016 at 6:06am