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Please answer using kinematics in 1 dimension and show completevanswers. a cement block accidentally falls from rest from the ledge of the 35.0 m...

Please answer using kinematics in 1 dimension and show completevanswers.


a cement block accidentally falls from rest from the ledge of the 35.0 m high building. When block is 14.0 m above the ground, a man 2.00 m tall looks up and noticed that the block is directly above him. How much time at most, does the man have to get out of the way? 

Top Answer

part 1: block falls 35-14= 21m  from equation of final velocity^2= initial velocity^2+ 2ad vf^2=vi^2+2ad a= gravitational... View the full answer

1 comment
  • i mean :time =-change in velocity/ acceleration= -(25.4323 -20.2879)/-9.8 = 0.52493 seconds
    • chrismathews125
    • Jul 20, 2016 at 6:06am

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Other Answers

Please see the attached... View the full answer

base solution14.pdf

a =9.81m/s 2 a= v/s  but v=d/s hence a =d/s 2 time to hit the ground =... View the full answer

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