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# Two identical guitar strings are prepared such that they have the same length (1.78 m) and are under the same amount of tension.

Two identical guitar strings are prepared such that they have the same length (1.78 m) and are under the same amount of tension. The first string is plucked at one location, primarily exciting the 5th harmonic. The other string is plucked in a different location, primarily exciting the 4th harmonic. The resulting sounds give rise to a beat frequency of 369 Hz. What is the wave propagation speed on the guitar strings?

let fundamental frequency = f 5f-4f =... View the full answer

wave speed = f * λ λ = 2 * (length of string) in... View the full answer

wave speed = f * λ λ = 2 * (length of string) in... View the full answer

The way to approach this... View the full answer

L=1.78m 5th harmonic-4th... View the full answer

The third harmonic - second harmonic = 369Hz (fundamental frequency) f=v/2L -&gt; v=f2L v= 369*2*1.78=... View the full answer

wave speed = f * λλ = 2 * (length of string)in this case... View the full answer

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