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A keg of beer is covered with a wet towel. Imagine that the keg gains energy from its surroundings at a rate of 20 W.

A keg of beer is covered with a wet towel. Imagine that the keg gains energy from its surroundings at a rate of 20 W.

Part A

At what rate in grams per second must water evaporate from a towel placed over the keg to cool the keg at the same rate that energy is being absorbed?

Part B

How much water in grams is evaporated in 2.0 h?

Top Answer

energy of water evaporated is given as :: Q = mL dividing both side by ''t'' Q/t = mL/t Q/t   is given... View the full answer

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