A keg of beer is covered with a wet towel. Imagine that the keg gains energy from its surroundings at a rate of 20 W.
At what rate in grams per second must water evaporate from a towel placed over the keg to cool the keg at the same rate that energy is being absorbed?
How much water in grams is evaporated in 2.0 h?
energy of water evaporated is given as :: Q = mL dividing both side by ''t'' Q/t = mL/t Q/t is given... View the full answer