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# For the circuit shown the emf of the battery is 1.50 kV, C = 9 F, R1 = R2 = R3 = 8.5 M and the capacitor is initially completely uncharged. Switch S...

For the circuit shown the emf of the battery is 1.50 kV, C = 9 µF, R­1 = R2 = R3 = 8.5 MΩ and the capacitor is initially completely uncharged. Switch S is suddenly closed at t = 0. What is the current through R­1 at t = 0?

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Since the capacitor is initially uncharged,  so at t=0, Capacitor acts as a short.  SO effectively there is... View the full answer

The answer is:         = 1.176  x 10 -4 A               Explanation      Since the capacitor is initially... View the full answer

1 comment
• Thank you for your patience. Any questions or clarification is welcomed.
• cplusplusexpert
• Jul 21, 2016 at 1:04pm

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