For the circuit shown the emf of the battery is 1.50 kV, C = 9 µF, R1 = R2 = R3 = 8.5 MΩ and the capacitor is initially completely uncharged. Switch S is suddenly closed at t = 0. What is the current through R1 at t = 0?
Since the capacitor is initially uncharged, so at t=0, Capacitor acts as a short. SO effectively there is... View the full answer