A 0.260-kg piece of aluminum that has a temperature of -162 °C is added to 1.2 kg of water that has a temperature of 1.8 °C. At equilibrium the temperature is 0 °C. Ignoring the container and assuming that the heat exchanged with the surroundings is negligible, determine the mass of water that has been frozen into ice.
let mass of ice formed be m , masss of water = ( 1.2 - m ) ; heat gained by aluminium = heat lost by water for... View the full answer
- hope it helps :)
- Jul 20, 2016 at 1:28pm