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# 260-kg piece of aluminum that has a temperature of -162 C is added to 1.2 kg of water that has a temperature of 1. At equilibrium the temperature is...

A 0.260-kg piece of aluminum that has a temperature of -162 °C is added to 1.2 kg of water that has a temperature of 1.8 °C. At equilibrium the temperature is 0 °C. Ignoring the container and assuming that the heat exchanged with the surroundings is negligible, determine the mass of water that has been frozen into ice.

let mass of ice formed be m , masss of water = ( 1.2 - m ) ; heat gained by aluminium = heat lost by water for... View the full answer

1 comment
• hope it helps :)
• J.Campbell
• Jul 20, 2016 at 1:28pm

Common temp = 0 So, heat gained by aluminium = 162 * 0.26 * 0.215*1000 cal                                  ... View the full answer

The answer is:      = 87.87 g              Explanation   From the principle of conservation of energy,    ... View the full answer

1 comment
• Thank you for your patience. Any questions or clarification is welcomed.
• cplusplusexpert
• Jul 21, 2016 at 1:13pm

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