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260-kg piece of aluminum that has a temperature of -162 C is added to 1.2 kg of water that has a temperature of 1. At equilibrium the temperature is...

A 0.260-kg piece of aluminum that has a temperature of -162 °C is added to 1.2 kg of water that has a temperature of 1.8 °C. At equilibrium the temperature is 0 °C. Ignoring the container and assuming that the heat exchanged with the surroundings is negligible, determine the mass of water that has been frozen into ice.

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let mass of ice formed be m , masss of water = ( 1.2 - m ) ; heat gained by aluminium = heat lost by water for... View the full answer

1 comment
  • hope it helps :)
    • J.Campbell
    • Jul 20, 2016 at 1:28pm

Other Answers

Common temp = 0 So, heat gained by aluminium = 162 * 0.26 * 0.215*1000 cal                                  ... View the full answer

The answer is:      = 87.87 g              Explanation   From the principle of conservation of energy,    ... View the full answer

1 comment
  • Thank you for your patience. Any questions or clarification is welcomed.
    • cplusplusexpert
    • Jul 21, 2016 at 1:13pm

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