A long string is moved up and down with simple harmonic motion with a frequencyof 42 Hz. The string is 543 m long and has a total mass is 47.2 kg. The string is fixed atboth ends. If the string is fixed at a length of 28 m we find a third harmonic standingwave.a)What is the tension in the string?b) How long would the string need to be to find the second harmonic standing wave?
a) tension v = (FT/μ) 1/2 v = f x 2l = 42 x 28x2 =2352 2352 = (FT /1.25663706 × 10 -6 ) 1/2... View the full answer