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The article cited in Exercise 11 also gave the following values of the variables y = number of culs-de-sac and z = number of intersections:

(y): 1, 0, 1, 0, 0, 2, 0, 1, 1, 1, 2, 1, 0, 0, 1, 1, 0, 1, 1, 1, 1, 0, 0, 0, 1, 1, 2, 0, 1, 2, 2, 1, 1, 0, 2, 1, 1, 0, 1, 5, 0, 3, 0, 1, 1, 0, 0

(z): 1, 8, 6, 1, 1, 5, 3, 0, 0, 4, 4, 0, 0, 1, 2, 1, 4, 0, 4, 0, 3, 0, 1, 1, 0, 1, 3, 2, 4, 6, 6, 0, 1, 1, 8, 3, 3, 5, 0, 5, 2, 3, 1, 0, 0, 0, 3

Construct a histogram for the y data. What proportion of these subdivisions had no culs-de-sac? At least one cul-de-sac?

Construct a histogram for the z data. What proportion of these subdivisions had at most five intersections? Fewer than five intersections?

#### Top Answer

Proportion of subdivisions had no culs-de-sac, Y: P(Y=0) = 4 6 1 7 Proportion of... View the full answer