Question 16-19 are related to the following

To test the hypothesis that the average daily visit to a state park during the season is 200, a random sample of 25 days yielded the following data (number of vehicles).

262 217 208 163 263

170 231 226 141 187

152 216 207 156 232

236 183 272 238 234

255 263 179 270 230

Test the hypothesis at a 5% level of significance.

16 The sample mean is,

a 215.64

b 217.80

c 219.97

d 222.17

17 The variance of the mean is,

a 65.39

b 64.23

c 63.60

d 62.97

18 The test statistic for the hypothesis test is,

a 2.214

b 2.109

c 1.971

d 1.577

19 Determine the critical value.

a CV = 2.064. Do not reject the null hypothesis. The mean is not different from 200.

b CV = 2.064. Reject the null hypothesis. The mean is different from 200.

c CV = 1.960. Do not reject the null hypothesis. The mean is not different from 200.

d CV = 1.960. Reject the null hypothesis. The mean is different from 200.

#### Top Answer

16) The sample mean is, = 1/ n * ∑xi = 215.64 a 215.64 17) The variance of the mean is, = (s/√n) 2 = ( 39.67564 / 5 ) 2 =... View the full answer