Men's heights are normally distributed with mean 68.9
68.9 in and standard deviation of 2.8 in.
2.8 in. Women's heights are normally distributed with mean 63.7
63.7 in and standard deviation of 2.5
2.5 in. The standard doorway height is 80
80 in. a. What percentage of men are too tall to fit through a standard doorway without bending, and what percentage of women are too tall to fit through a standard doorway without bending? b. If a statistician designs a house so that all of the doorways have heights that are sufficient for all men except the tallest 5%, what doorway height would be used?
the PDF of normal distribution is = 1/σ * √2π * e ^ -(x-u)^2/ 2σ^2 standard normal distribution is a normal distribution... View the full answer