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Please kindly assist with finding the correct answers to the following questions. Thank you!

14 wrong.pngPlease kindly assist with finding the correct answers to the following questions. Thank you!!13 wrong.png9 wrong.png

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A studv was to be undertaken to determhe if a particular trahlng program would
lmprove physical fitnus. An 5R5 of 31 universitv students was selected to be enrolled
in the fitness program. One important memure ol‘ fitness is maxiern oat-gen uptake.
Measurements of ottvgen uptalue ln untralned lndlviduals are ltnovm to follow a Normal
dlstrlbutlon Ii-l'lth a mean of .u- = 45 mLfltgr'mln. The researchers ltd-shed to deten'nhe If
there was evidence that tnelr sample of students dll'fered from the general poleatlon
of untralned subjects. The measurements made on flte subjects coming into thls studv
produced a mean of 5 = 414 with a standard deviation o'Fs = 5.3. If the 93%. confidence Interval for the population mean oat-men uptalue alter trainlng
was determined to be {45.2. 4915!. what would the researcl'iers oonclude? The sample is not staristicallv significant at the D132 level. ' The sarmle mean ls signlhcmtlvdll’ferent fromfl . 45 at flieDB-l level There would be no reason to believe the selected students come from a different
population. There is statisticallv sufficient evidence at significance level D20 to conclude that the
sample comes from a population with a mean different fmm .ll — 45-. The true mean owl-"gen uptake for these students is .l-I'r - r15.

Top Answer

13 . df = 12+15-2 =25 14. in excel :- p value is, =T.DIST.2T(2.1,25) = 0.045 0.01 < p... View the full answer

1 comment
  • 13. df= 12 - 1 = 11
    • gawt124
    • Apr 05, 2018 at 5:26am

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